Question

БУДЬЛАСКА МОЖНА С ПОЯСНЕНЯМ Розв'яжіть рiвняння: 1) 3x + 6 : 0; 2) 2x² +8 x-1 = 2x.​

Answer 1

$\displaystyle\bf\\1)\\\\\frac{3x+6}{x-4} =0\\\\\\\left \{ {{3x+6=0} \atop {x-4\neq 0}} \right. \\\\\\\left \{ {{3x=-6} \atop {x\neq 4}} \right. \\\\\\\left \{ {{x=-2} \atop {x\neq 4}} \right. \\\\\\Otvet \ : \ -2\\\\2)\\\\\frac{2x^{2} +8}{x-1} =2x\\\\\\\frac{2x^{2} +8}{x-1} -2x=0\\\\\\\frac{2x^{2} +8-2x^{2} +2x}{x-1} =0\\\\\\\frac{2x+8}{x-1} =0\\\\\\\left \{ {{2x+8=0} \atop {x-1\neq 0}} \right. \\\\\\\left \{ {{2x=-8} \atop {x\neq 1}} \right.$

$\displaystyle\bf\\\left \{ {{x=-4} \atop {x\neq 1}} \right. \\\\\\Otvet \ : \ -4$