Question

СРОЧНО Даю 28 Баллов!!!!!!!!!!!!!!! Розв'язати вираз ​

Answer 1

Відповідь:

Пояснення:

Answer 2

Ответ:

$\dfrac{1}{16x^2-4x}$

Объяснение:

$\left( \dfrac{4x+1}{4x-1}-\dfrac{4x-1}{4x+1}\right)\div\dfrac{64x^2}{4x+1}=\\\\\\=\left( \dfrac{(4x+1)(4x+1)}{(4x-1)(4x+1)}-\dfrac{(4x-1)(4x-1)}{(4x+1)(4x-1)}\right)\div\dfrac{64x^2}{4x+1}=\\\\\\=\left( \dfrac{(4x+1)(4x+1)-(4x-1)(4x-1)}{(4x-1)(4x+1)}\right)\div\dfrac{64x^2}{4x+1}=\\\\\\=\left( \dfrac{(4x+1)^2-(4x-1)^2}{(4x-1)(4x+1)}\right)\div\dfrac{64x^2}{4x+1}=\\\\\\=\left( \dfrac{4x^2+8x+1-(4x^2-8x+1)}{(4x-1)(4x+1)}\right)\div\dfrac{64x^2}{4x+1}=$

$=\left( \dfrac{4x^2+8x+1-4x^2+8x-1}{(4x-1)(4x+1)}\right)\div\dfrac{64x^2}{4x+1}=\\\\\\= \dfrac{8x+8x}{(4x-1)(4x+1)}\div\dfrac{64x^2}{4x+1}=\dfrac{16x}{(4x-1)(4x+1)}\times\dfrac{4x+1}{64x^2}=\\\\\\=\dfrac{1}{4x-1}\times\dfrac{1}{4x}=\boxed{\dfrac{1}{16x^2-4x}}$