Question

допоможіть будь ласка!!!
((x^(2)-5x)/(x^(2)-10x+25)+(25)/(x^(2)-25))*(5+x)/(125-x^(3))
8 клас

Answer 1

Объяснение:

вот, конечно не уверена на все 100%. но надеюсь помогла!)

Answer 2

Ответ:

$-\dfrac{1}{(x-5)^2}$

Объяснение:

$\displaystyle\\\\\left(\frac{x^2-5x}{x^2-10x+25}+\frac{25}{x^2-25}\right)\times\frac{5+x}{125-x^3}\\\\\\\left(\frac{x(x-5)}{(x-5)^2}+\frac{25}{(x-5)(x+5)}\right)\times\frac{5+x}{(5-x)\left( x^{2}+5x+25\right) }\\\\\\\left(\frac{x}{(x-5)}+\frac{25}{(x-5)(x+5)}\right)\times\frac{5+x}{(5-x)\left( x^{2}+5x+25\right) }\\\\\\\left(\frac{x(x+5)+25}{(x-5)(x+5)}\right)\times\frac{5+x}{(5-x)\left( x^{2}+5x+25\right) }$

$\displaystyle\\\frac{x^2+5x+25}{(x-5)(x+5)}\times\frac{5+x}{(5-x)\left( x^{2}+5x+25\right) }\\\\\\\frac{1}{(x-5)}\times\frac{1}{(5-x) }=\frac{1}{(x-5)}\times\frac{1}{-(x-5) }=\boxed{-\frac{1}{(x-5)^2}}$