Question

Довести тотожність ааааааа срочно

Answer 1

Объяснение:

1)

$\displaystyle\\\frac{a+4}{a^2-6a+9}:\frac{a^2-16}{2a-6} =\frac{a+4}{(a-3)^2}:\frac{a^2-16}{2*(a-3)}=\frac{a+4}{(a-3)^2}*\frac{2*(a-3)}{(a+4)*(a-4)} =\\\\\\ =\frac{2}{(a-3)*(a-4)}.$

2)

$\displaystyle\\\frac{2}{(a-3)*(a-4)} -\frac{2}{a-4} =\frac{2-2*(x-3)}{(a-3)*(a-4)}=\frac{2-2x+6}{(a-3)*(a-4)}=\\\\\\=\frac{-2x+8}{(a-3)*(a-4)}=-\frac{2*(x-4)}{(a-3)*(a-4)}=-\frac{2}{a-3} =\frac{2}{3-x}.$