• Предмет: Математика
  • Автор: mashaton111
  • Вопрос задан 1 месяц назад

(x-19)(x^2+1)(sin^2 x+1)(lg^2x+1)(2 (171,43x))=0​

Ответы

Ответ дал: masterbrainly2023
1

Ответ:

To solve the equation:

(x - 19)(x^2 + 1)(sin^2 x + 1)(lg^2x + 1)(2 (171,43x)) = 0

We can use the zero product property, which states that if a product of factors is equal to zero, then at least one of the factors must be zero. Therefore, we can set each factor equal to zero and solve for x.

Setting each factor equal to zero:

x - 19 = 0

x^2 + 1 = 0

sin^2 x + 1 = 0

lg^2x + 1 = 0

2 (171,43x) = 0

Solving each equation:

x - 19 = 0

x = 19

x^2 + 1 = 0

x^2 = -1

This equation has no real solutions since the square of a real number cannot be negative.

sin^2 x + 1 = 0

sin^2 x = -1

This equation also has no real solutions since the square of the sine function cannot be negative.

lg^2x + 1 = 0

lg^2x = -1

Similar to the previous equations, this equation has no real solutions.

2 (171,43x) = 0

171,43x = 0

x = 0

Therefore, the solutions to the given equation are x = 0 and x = 19.

Пошаговое объяснение:

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