Question

x²/3=9-2x через дискриминант​

Answer 1

$\displaystyle\bf\\\frac{x^{2} }{3} =9-2x\\\\\\\frac{x^{2} }{3}\cdot 3 =9\cdot 3-2x\cdot 3\\\\\\x^{2} =27-6x\\\\\\x^{2} +6x-27=0\\\\\\D=6^{2} -4\cdot(-27)=36+108=144=12^{2} \\\\\\x_{1} =\frac{-6-12}{2} =\frac{-18}{2} =-9\\\\\\x_{2} =\frac{-6+12}{2} =\frac{6}{2} =3\\\\\\Otvet \ : \ -9 \ ; \ 3$