• Предмет: Алгебра
  • Автор: bp4zxy7zw4
  • Вопрос задан 1 месяц назад

Log²₂x²-3log₂ x -16=


bena20193: равно 0?

Ответы

Ответ дал: Vetal2912
0

Ответ:

The expression you provided is a logarithmic expression. To solve it, we can use the following steps:

Apply the power rule of logarithms to the first term: log₂(x²)² = 2log₂(x²).

Distribute the negative sign in the second term: -3log₂(x).

Combine the first two terms: 2log₂(x²) - 3log₂(x).

Use the quotient rule of logarithms to simplify the expression: log₂(x²/2³) = log₂(x²/8).

Subtract 16 from the simplified expression: log₂(x²/8) - 16.

Therefore, the simplified expression is log₂(x²/8) - 16.

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