Question

Определите sin a, cos a, tg a, если cos a=0,6 ! Срочно

Answer 1

$sin^{2} alpha + cos^{2} alpha =1$
$sinalpha = sqrt{1- cos^{2} alpha } = sqrt{1- 0.6^{2} } = sqrt{0.64} =0.8$

$tg alpha = frac{sin alpha }{cos alpha } = frac{0.8}{0.6} =[tex]1 frac{1}{3}$

Answer 2

sin²a+cos²a=1
$sinalpha=sqrt{1-cos^{2}alpha}=sqrt{1-0,6^{2}}=sqrt{1-0,36}=sqrt{0,64}=0,8$
$tgalpha=frac{sinalpha}{cosalpha}=frac{0,8}{0,6}=[tex]1frac{1}{3}$ [/tex]