Question

Обчислити масові частки елементів у сполуках: Na2S, CaC2, C2H2, Ba(NO3)2, Al2(SO4)3.допоможит будласка даю 50б)

Answer 1

Ответ:

Объяснение:

Mr(Na2S) = 2Ar(Na) + Ar(S) = 2 * 23 + 32 = 78

w(Na) = Ar(Na) * n/Mr(Na2S) * 100% = 23 * 2/78 * 100% = 59%

w(S) = Ar(S) * n/Mr(Na2S) * 100% = 32/78 * 100% = 41%

Mr(CaC2) = Ar(Ca) + Ar(C) * 2 = 40 + 12 * 2 = 64

w(Ca) = Ar(Ca) * n/Mr(CaC2) * 100% = 40/64 * 100% = 62,5%

w(C) = Ar(C) * n/Mr(CaC2) * 100% = 12 * 2/64 * 100% = 37,5%

Mr(C2H2) = Ar(C) * 2 + Ar(Н) * 2 = 12 * 2 + 1 * 2 = 26

w(C) = Ar(C) * n/Mr(C2H2) * 100% = 12 * 2/26 * 100% = 92,31%

w(Н) = Ar(Н) * n/Mr(C2H2) * 100% = 1 * 2/26 * 100% = 7,69%

Mr(Ba(NO₃)₂) = Ar(Вa) + Ar(N) * 2 + Ar(О) * 6 = 137 + 14 * 2 + 16 * 6 = 261

w(Ba) = Ar(Вa) * n/Mr(Ba(NO₃)₂) * 100% = 137/261 * 100% = 52,49%

w(N) = Ar(N) * n/Mr(Ba(NO₃)₂) * 100% = 14 * 2/261 * 100% = 10,73%

w(O) = Ar(О) * n/Mr(Ba(NO₃)₂) * 100% = 16 * 6/261 * 100% = 36,78%

Mr(Al₂(SO₄)₃) = Ar(Al) * 2 + Ar(S) * 3 + Ar(О) * 12 = 2*27 + 3*32 + 12*16 = 342

w(Al) = Ar(Al) * n/Mr(Al₂(SO₄)₃) * 100% = 27 * 2/342 * 100% = 15,79%

w(S) = Ar(S) * n/Mr(Al₂(SO₄)₃) * 100% = 32 * 3/342 * 100% = 28,07%

w(O) = Ar(О) * n/Mr(Al₂(SO₄)₃) * 100% = 16 * 12/342 * 100% = 56,14%