Question

x^2+y^2=16 y= -x-4
Срочно нужно

Answer 1

Ответ: (0;-4),  (-4;0).

Пошаговое объяснение:

$\displaystyle\\\\\left \{ {{x^2+y^2=16} \atop {y=-x-4}} \right.\ \ \ \ \ \left \{ {{x^2+y^2=16} \atop {y=-(x+4)}} \right.\ \ \ \ \ \ \left \{ {{x^2+y^2=16} \atop {y^2=(-(x+4))^2}} \right.\ \ \ \ \ \ \left \{ {{x^2+(x+4)^2=16} \atop {y^2=(x+4)^2}} \right. \\\\\\\left \{ {{x^2+x^2+8x+16=16} \atop {y=-x-4}} \right.\ \ \ \ \ \ \left \{ {{2x^2+8x=0\ |:2} \atop {y=-x-4}} \right.\ \ \ \ \ \ \left \{ {{x^2+4x=0} \atop {y=-x-4}} \right.$

$\displaystyle\\\left \{ {{x*(x+4)=0} \atop {y=-x-4}} \right. \ \ \ \ \ \ \left \{ {{x_1=0\ \ \ \ \ \ \ \ \ \ x_2=-4} \atop {y_1=-4\ \ \ \ \ \ y_2=0}} \right. .$