Question

ОЧ СРОЧНО, ДАЮ ВСЕ БАЛЫ​

Answer 1

Ответ:

Объяснение:

СО2    PCl5    NaBr   Fe2O3     SF4

Mr(СО2) = Ar(С) + 2Ar(О) = 12 + 2 * 16 = 44

w(C) = Ar(C)/Mr(СО2) * 100% = 12/44 * 100% = 27%

w(О) = 2Ar(О)/Mr(СО2) * 100% = 2* 16/44 * 100% = 73%

Mr(PCl5) = Ar(P) + 5Ar(Cl) = 31 + 5 * 35,5 = 208,5

w(P) = Ar(P)/Mr(PCl5) * 100% = 31/208,5 * 100% = 14,87%

w(Cl) = 2Ar(Cl)/Mr(PCl5) * 100% = 5 * 35,5/208,5 * 100% = 85,13%

Mr(NaBr) = Ar(Na) + Ar(Br) = 23 + 80 = 103

w(Na) = Ar(Na)/Mr(NaBr) * 100% = 23/103 * 100% = 22,33%

w(Br) = Ar(Br)/Mr(NaBr) * 100% = 80/103 * 100% = 77,67%

Mr(Fe2O3) = 2Ar(Fe) + 3Ar(О) = 2 * 56 + 3 * 16 = 160

w(Fe) = Ar(Fe)/Mr(Fe2O3) * 100% = 2 * 56/160 * 100% = 70%

w(О) = 2Ar(О)/Mr(Fe2O3) * 100% = 3* 16/160 * 100% = 30%

Mr(SF4 ) = Ar(S) + 4Ar(F) = 32 + 4 * 19 = 108

w(S) = Ar(S)/Mr(SF4 ) * 100% = 32/108 * 100% = 29,63%

w(F) = 2Ar(F)/Mr(SF4 ) * 100% = 4 * 19/108 * 100% = 70,37%