Question

Помогите пожалуйста номер 6,7 даю 15б!

Answer 1

Объяснение:

=(6-m)(6+m)/(m-8)•(m/(m-6)-2m/((m-6)²))+12m/(m-6)=

=(6-m)(6+m)/(m-8)•(m²-6m-2m)/(m-6)²+12m/(m-6)=

= -(m-6)(m+6)/(m-8)•(m²-8m)/(m-6)²+12m/(m-6)=

= -(m+6)/(m-8)•(m(m-8))/(m-6)+12m/(m-6)=

= -m(m+6)/(m-6)+12m/(m-6)=

= (-m²-6m+12m)/(m-6)=(-m²+6m)/(m-6)=

= -m(m-6)/(m-6)= -m

(2x-1)/(2x+1) + 2x/(2x-1)=2

(2x-1)/(2x+1) + 2x/(2x-1)-2=0

(2x-1)(2x-1) + 2x(2x+1) - 2(4x²-1)=0

4x²-2x-2x+1+4x²+2x-8x²+2=0

-2x+3=0

-2x= -3

x=1,5