Question

5 прошу васссссссссс

Answer 1

Ответ:

\((x-2)(x^2-x+3)-(x^2+5)(x-3) = 9\)

\(x^3 - x^2 + 3x - 2x^2 + 2x - 6 - x^2 - 5x + 15 = 9\

\(x^3 - 5x^2 - 5x + 9 = 0\)

\(x^3 - 5x^2 - 5x + 9 = (x-3)(x^2-2x-3)\)

\((x-3)(x^2-2x-3) = 0\)

\(x = 3\) \(x^2-2x-3 = 0\)

\(x^2-2x-3 = 0\)

\(x = \frac{2 \pm \sqrt{2^2-4(-3)}}{2} = \frac{2 \pm \sqrt{16}}{2} = \frac{2 \pm 4}{2}\)

1. \(x = 3\)

2. \(x = \frac{6}{2} = 3 + 2 = 5\)

3. \(x = \frac{-2}{2} = 3 - 1 = 2\)

1. \(x = 3\): \(3^3 - 5(3)^2 - 5(3) + 9 = 27 - 45 - 15 + 9 = -24 \neq 9\)

2. \(x = 5\): \(5^3 - 5(5)^2 - 5(5) + 9 = 125 - 125 - 25 + 9 = -16 \neq 9\)

3. \(x = 2\): \(2^3 - 5(2)^2 - 5(2) + 9 = 8 - 20 - 10 + 9 = -13 \neq 9\)

\[x = 3, 5, 2\]