Question

(x+3)(x-2)-(x+4)(x-1)=3x;
15x²-(3x-2) (5x+4)=16;

Answer 1

Ответ:

(х+3)(х-2)-(х+4)(х-1)=3х

х²-2х+3х-6-(х²-х+4х-4)=3х

х²-2х+3х-6-(х²+3х-4)=3х

х²-2х-6-х²-3х+4=0

-5х-2=0

-5х=2

х= -2/5.

15х²-(3х-2)(5х+4)=16

15х²-(15х²+12х-10х-8)=16

15х²-(15х²+2х-8)=16

15х²-15х²-2х+8=16

-2х+8=16

-2х=16-8

-2х=8

х-4.