Question

- Решите уравнения помогите ​

Answer 1

Объяснение:

A)

$3x^2-8*|x|+5=0$

Раскрываем модуль - получаем совокупность уравнений:

$\displaystyle\\\left [ {{3x^2-8*x+5=0} \atop {3x^2-8*(-x)+5=0}} \right. \ \ \ \ \ \ \left [ {{3x^2-8x+5=0} \atop {3x^2+8x+5=0}} \right. \ \ \ \ \ \ \left [ {{3x^2-3x-5x+5=0} \atop {3x^2+3x+5x+5=0}} \right. \\\\\\\left [ {{3x*(x-1)-5*(x-1)=0} \atop {3x*(x+1)+5*(x+1)=0}} \right.\ \ \ \ \ \ \left [ {{(x-1)*(3x-5)=0} \atop {(x+1)*(3x+5)=0}} \right.\ \ \ \ \ \ \left [ {{x_1=1\ \ \ \ x_2=\frac{5}{3} } \atop {x_3=-1\ \ \ \ x_4=-\frac{5}{3} }} \right. .$

Б)

$\displaystyle\\\frac{15}{x}-\frac{6}{x-2}=1\\\\\\15*(x-2)-6*x=1*x*(x-2)\\\\15x-30-6x=x^2-2x\\\\x^2-11x+30=0\\\\x^2-6x-5x+30=0\\\\x*(x-6)-5*(x-6)=0\\\\(x-6)*(x-5)=0\\\\x-6=0\\\\x_1=6.\\\\x-5=0\\\\x_2=5.$

Ответ: x₁=6, x₂=5.