Question

помогите пж решить хоть 2 задание даю 70 балов ​

Answer 1

Ответ:

№1

1) $\frac{4x + 8}{x + 2} - \frac{x - 4}{x + 2} = \frac{4x + 8 - x + 4}{x + 2} = \frac{3x + 12}{x + 2}$

2) $\frac{x}{x - 4} - \frac{16}{ {x}^{2} - 4x} = \frac{ {x}^{2} - 16}{ {x}^{2} - 4x } = \frac{(x - 4)(x + 4)}{x(x - 4)} = \frac{x + 4}{x}$

№2

1) $245000 = 2.45 \times {10}^{5}$

2) $0.0019 = 1.9 \times {10}^{ - 3}$

№3

1) ${x}^{ - 3} \times {x}^{5} = {x}^{2}$

2) ${x}^{ - 6} \div {x}^{ - 8} = {x}^{2}$

3) ${( {x}^{5}) }^{ - 3} \times {x}^{18} = {x}^{ - 15} \times {x}^{18} = {x}^{3}$

4) пример плохо видно

5) ${( - \frac{2}{3} {x}^{ - 4} {y}^{ - 8}) }^{ - 2} \times {(3 {x}^{2} {y}^{12} )}^{ - 3} = \frac{9}{4} {x}^{8} {y}^{16} \times \frac{1}{27} {x}^{ - 6} {y}^{ - 36} = \frac{1}{12} {x}^{2} {y}^{ - 20}$