Question

Допоможіть будь ласка

Answer 1

$\displaystyle\bf\\1)\\\\2^{-1}+3^{-2} =\frac{1}{2} +\frac{1}{3^{2} } =\frac{1}{2} +\frac{1}{9} =\frac{9+2}{2\cdot 9} =\frac{11}{18} \\\\2)\\\\\Big(\frac{5}{6} \Big)^{-3} \cdot\Big(-3\frac{3}{7} \Big)^{-2} =\Big(\frac{6}{5} \Big)^{3} \cdot\Big(-\frac{24}{7} \Big)^{-2} =\\\\\\=\Big(\frac{6}{5} \Big)^{3} \cdot\Big(\frac{7}{24} \Big)^{2} =\frac{6^{3} \cdot 49}{125\cdot 6^{2} \cdot16} =\frac{294}{2000} =0,147$