Question

помогите пжпжпж
в низу
​

Answer 1

$1. \: y = \frac{1}{ \sqrt{18 - 9x} }$

18 - 9x > 0

-9x > - 18

x < 2

xЄ(-∞; 2)

$2) \: y = \frac{17x}{3x {}^{2} + 14x - 5 }$

3х² + 14х - 5 ≠ 0

D = b² - 4ac = 14² - 4×3×(-5) = 256

x1 = (-b - √D)/2a = (-14 - 16)/6 = -5

x2 = (-b + √D)/2a = (-14 + 16)/6 = 1/3

xЄ(-∞; -5)U(-5; 1/3)U(1/3; +∞)