Question

ПЕПЕР ПОМОГИ ДАЮ 100 БАЛОВ!!!

Answer 1

$\displaystyle\bf\\1)\\\\\frac{4^{n+3}+4^{n+1} }{17} =\frac{4^{n+1}\cdot(4^{2}+1) }{17} =\frac{4^{n+1}\cdot(16+1) }{17}=\\\\\\=\frac{4^{n+1}\cdot 17 }{17} =4^{n+1} \\\\2)\\\\\frac{x^{5}+x^{9} }{x^{-1}+x^{3} } =\frac{x^{5} \cdot(1+x^{4} )}{x^{-1} \cdot(1+x^{4} )} =\frac{x^{5} }{x^{-1} } =x^{5-(-1)} =x^{5+1} =x^{6}$