Question

2Al + 6HCl= 2AlCl3 + 3H2 + 623kJ Find how much energy is released if 534g of AlCl3 is produced

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Answer 1

Ответ:

Объяснение:To find out how much energy is released if 534g of AlCl3 is produced, we can use the balanced chemical equation and the given enthalpy change (∆H) of the reaction.

The balanced chemical equation for the reaction is:

2Al + 6HCl → 2AlCl3 + 3H2 + 623 kJ

From the balanced equation, we can see that 2 moles of AlCl3 are produced for every mole of AlCl3. This means that the molar mass of AlCl3 is needed to determine the number of moles produced from the given mass.

The molar mass of AlCl3 can be calculated as follows:

Al: 26.98 g/mol

Cl: 35.45 g/mol x 3 = 106.35 g/mol

Molar mass of AlCl3 = 26.98 g/mol + 106.35 g/mol = 133.33 g/mol

Now, we can calculate the number of moles of AlCl3 produced using the given mass:

Number of moles = Mass / Molar mass

Number of moles = 534 g / 133.33 g/mol ≈ 4 moles

Since the reaction releases 623 kJ of energy per 2 moles of AlCl3, we can calculate the energy released for the given amount:

Energy released = (4 moles / 2 moles) x 623 kJ

Energy released = 2 x 623 kJ

Energy released = 1246 kJ

Therefore, if 534g of AlCl3 is produced, approximately 1246 kJ of energy will be released.