Question

Решите уравнение:

а) 16с2-49=0

б) (2х-5)2-(2х-3)(2х+3)=0

Answer 1

1) 16С^2 = 49 
     C^2 = 49/16 
     C1 = V ( 49/16 ) = V 49 / V 16 = 7 / 4 = 1 3/4 = 1.75 
     C 2 = ( - 1.75 )
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2) 4X^2 - 20X + 25 - ( 4X^2 - 9 ) = 0 
4X^2 - 20X + 25 - 4X^2 + 9 = 0
- 20X + 34 = 0 
20X = 34 
X = 34/20 = 1.7