Question

Решить деление

6p³/p³-q³:2p²/p²+2pq+q²

Answer 1

6p³/p³-q³:2p²/p²+2pq+q²=6p³/p³-q³*(p+q)²/2p²=3p(p+q)²/p³-q³
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если 6p³/p³-q³:2p²/p²+pq+q²=6p³/(p-q)(p²+pq+q²)*p²+2pq+q²/2p²=3p/(p-q)

Answer 2

$frac{6p^3}{p^3-q^3}:frac{2p^2}{p^2+pq+q^2}=frac{6p^3}{(p-q)(p^2+pq+q^2)}cdotfrac{p^2+pq+q^2}{2p^2}=frac{3p}{p-q}$