Question

Решите неравенство 

в) 2(3-2z)+3(2-z)<40

г) -(8t-2)-2(t-3)>0

Answer 1

6-4z+6-3z<40

12-7z<40

-7z<40-12

-7z<28/(-7)

z>4

ответ;4

-8t+2-2t+6>0

-10t+8>0

-10t>-8/(-10)

t<0.8