Question

Решить уравнение
($frac{1}{8}) ^{4x+3}$ = 64$^{x-1}$

Answer 1

$(frac{1}{8})^{4x+3}= ( frac{1}{8} )^{2-2x}$

$4x+3=2-2x \6x=-1 \x=- frac{1}{6}$