Question

а(в шестой степени)минус 8

Answer 1

$a^{6}-8=(a^{2})^{3}-2^{3}=(a^{2}-2)(a^{4}+2a^{2}+4)=$
$=(a- sqrt{2})(a+ sqrt{2})(a^{4}+2a^{2}+4)$