Question

lim x стремится к -5  2x^2+7x-15/3x^2+20x+25

Answer 1

2x²+7x-15=(x+5)(2x-3)
D=49+120=169
x1=(-7-13)/4=-5
x2=(-7+13)/4=3/2
3x²+20x+25=(x+5)(3x+5)
D=400-300=100
x1=(-20-10)/6=-5
x2=(-20+10)/6=-5/3
lim(2x²+7x-15)/(3x²+20x+25)=lim(x+5)(2x-3)/(x+5)(3x+5)=lim(2x-3)/(3x+5)=
(2*(-5)-3)/(3*(-5)+5)=-13/-10=1,3