Question

log3X+log3(x+6)=3

 

lg 12(3x-10) больше или равно двум

Answer 1

1.log3X+log3(x+6)=3

log3x(x+6)=3log3(3)

x(x+6)=27

x^2+6x-27=0

x1=-9

x2=3

2. log1/2(3x-10)≥2

-log2(3x-10)≥2

log2(3x-10)≤-2

3x-10>0

3x>10

x>10/3

 

3x-10≤1/4

3x≤1/4+10

3x=41/4

x≤41/12