Question

решите уравнение x^2 + 4x - 8=0

Answer 1

$x^2+4x-8=0\\ a = 1, b = 4, c = -8 \\ D= b^2 - 4ac=16+4cdot8=16+32=48 \\ x_{1,2}=cfrac{-b pm sqrt{D}}{2a}=cfrac{-4 pm sqrt{48}}{2}=cfrac{-4 pm 4sqrt3}{2}=-2pm 2sqrt3$

Ответ: $-2pm 2sqrt3$