Question

найти корни уравнения: 4х+1= 9 дробь х-1
помогите..

Answer 1

4x+1=9/(x-1)
(4x+1)*(x-1)=9
4x²+x-4x-1=9
4x²-3x-10=0
x₁=(-(-3)+√(-3)²+4*4*(-10))/2*4=(3+√(9+160))/8=(3+13)/8=2
x₂=(-(-3)-√(-3)²+4*4*(-10))/2*4=(3-√(9+160))/8=(3-13)/8=-1,25