Question

R1-10OM. R2=15 OM,R3=12OM,R4=6 OM,R5=4OM,U2=60В. НАЙТИ силу тока

Answer 1

1/R12 = 1/R1+1/R2 = (R1+R2) / (R1*R2);R12 = (R1*R2) / (R1+R2) = (4*6) / (4+6) = 24/10=2.4 Ом 1/R345 = 1/R3+1/R4+1/R5 = 1/12+1/12+1/6 = (1+1+2)/12 = 4/12R345 = 12/4 =3 Ом R = R12 +R345 = 2.4+3 = 5.4 Ом