Question

Найдите производную:

1) -3sin2x+5cos3x-7

2) sin(3x- 2Пи/3)

Answer 1

1) y'=-3cos2x*2-5sin3x*3 = -6cos2x-15sin3x

2) y'=cos(3x-(2pi)3)*3 = 3cos(3x-(2pi3))

Answer 2

Решение

1 y'=-3cos2x*2-5sin3x*3 = -6cos2x-15sin3x

2 y'=cos(3x-(2pi)3)*3 = 3cos(3x-(2pi3))