Question

1-cosX- 2sinX/2=0
Помогите решить

Answer 1

x/2 заменяем на t1-cos2t-2sint=01-(1-2sin^2t)-2sint=01-1+2sn^2t-2sint=0sin^2t-sint=0sint(sint-1)=0sint=0         sint=1t=(pi)*k        t=(pi)/2+2(pi)*nx=2(pi)*k     x=(pi)+4(pi)*n