Question

log6(x^2+7x)=log 6(x^2+14)

Answer 1

log6(x^2+7x)=log 6(x^2+14)
ОДЗ x^2+7x>0
=====-7======0=======
+++++   ----------    +++++
x^2+7x=x^2+14
7x=14
x=2

Answer 2

спасибо