Question

решите систему Х+У=3 Х в квадрате+У в квадрате= 25+2ХУ

Answer 1

$left { {{{x+y=3} atop {x^2+y^2=25+2xy}} right. \ left { {{{x+y=3} atop {x^2+y^2-2xy=25}} right. \ left { {{{x+y=3} atop {(x-y)^2=25}} right. \ left { {{{x=3-y} atop {(3-y-y)^2=25}} right. \ left { {{{x=3-y} atop {(3-2y)^2=25}} right. \ left { {{{x=3-y} atop {3-2y=5}} right. left { {{{x=3-y} atop {3-2y=-5}} right. \ left { {{2y=-2} atop {x=3-y}} right. left { {{{2y=8} atop {{x=3-y}} right. \ left { {{y=-1} atop {x=3-y}} right. left { {{{y=4} atop {{x=3-y}} right. \ left { {{y=-1} atop {x=4}} right. left { {{{y=4} atop {{x=-1}} right.$