Question

7-3(Х-1)=2х
(Х+4)^2=х(х+3)

Answer 1

1)7-3(x-1)=2x
7-3x+3=2x
-5x=-7-3
-5x=-10
x=2

2)(x+4)²=x(x+3)
x²+8x+16=x²+3x
x²-x²+8x-3x=-16
5x=-16
x=-$frac{12}{5}$=-2$frac{2}{5}$