Question

1) sin^2x-sinx=0
2) ctg^2x-4ctg x= 0
3) корень с 3 cos2x + sin2x = 0

Answer 1

1) sin^2x-sinx=0
Sinx(sinx-1)=0
Sinx=0
X=пk
Sinx-1=0
Sinx=1
X=п/2+2пk

Answer 2

ctg^2x-4ctgx=0

Answer 3

Спасибо большое)

Answer 4

$1) sin^2x-sinx=0\ sinx(sinx-1)=0\ sinx=0 sinx=1\ x=pi k, x=frac{pi}{2}+pi k k E Z \ x=frac{pi}{2}+frac{pi k}{2}; k E Z.\ 2) ctg^2x-4ctgx=0\ ctgx(ctgx-4)=0\ ctgx=0 ctgx=4\ x=pi k x=arcctg4+pi k; k E Z\ 3) sqrt3cos2x+sin2x=0\ frac{sqrt3}{2}cos2x+frac{1}{2}sin2x=0\ cos(frac{pi}{6})*cos2x+sin(frac{pi}{6})*sin2x=0\ cos(2x-frac{pi}{6})=0$
$2x-frac{pi}{6}=frac{pi}{2}+pi k; k E Z\ 2x=frac{2pi}{3}+pi k\ x=frac{pi}{3}+frac{pi k}{2}$