Question

9/x-3 - 3x/(x-3)^2 : 3x/x^2-9 - 2x-3/x-3
упростите при х=2-корень7

Answer 1

3x/(x-3)² : 3x/x²-9 =3x*(x-3)(x+3)/(x-3)² *3x=(x+3)/(x-3)
9/(x-3) - (x+3)/(x-3) -(2x-3)/(x-3)=(9-x-3-2x+3)/(x-3)=(9-3x)/(x-3)=-3(x-3)/(x-3)==-3

Answer 2

Спасибо!