Question

(2x-1)(2x+1)=(2x+3)во 2 степени.=38

Answer 1

(2x-1)(2x+1)=(2x+3)^2=38 (4x^2+2x-2x-1)=4x^2+12x+9=38 4x^2-1-4x^2-12x-9-38=0 -12x-1-9-38=0 -12x-48=0 x=-4