Question

сократите дробь: 18^(n+3)/3^(2n+5)*2^(n-2)

Answer 1

18^(n+3)/3^(2n+5)*2^(n-2)=3^(2n+6)*2^(n+3)/3^(2n+5)*2^(n-2)=3^(2n+6-2n-5)*2^(n+3-n+2)=3*2^5=3*32=96 
по свойствам действий со степенями.