Question

Дана функция y = f(x), где f(x) = 12x - 5. Найдите:
a) f(x+1); б) f(x^2); в) f(-x); г) f(x^2 - 3)

Answer 1

 F ( X ) = 12X - 5 
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F ( X + 1 ) = 12 * ( X + 1 ) - 5 = 12X + 12 - 5 = 12X + 7 
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F ( X^2 ) = 12 X^2 - 5 
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F ( - X ) = 12 * ( - X) - 5 = - 12X - 5 
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F ( X^2 - 3 ) = 12 * ( X^2 - 3 ) - 5 = 12X^2 - 36 - 5 = 12X^2 - 41