Question

y$2 x^{3} -32x- x^{2} +16=0$

Answer 1

2х(х²-16)-(х²-16)=0
(2х-1)(х²-16)=0
2х₁-1=0
х₁=1/2
х²-16=0
х²=16
х₂=4
х₃=-4