Question

a)3c+3c^-a-ac=?
b)2x^ -3x+4ax-6a=?

Answer 1

а)3c+3c^-a-ac=3с(1+с)-а(1+с)=(3с-а)(1+с)
б)2x^ -3x+4ax-6a=2x^+4ах-3х-6а=2х(х+2а)-3(х+3а)=(2х-3)(х+2а)