Question

al -> alcl3->al(oh)2->al2o3->al->na[al(oh)6]->al2(so4)3
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Answer 1

2 Al +6 HCl = 2Al Cl3 +3H2

AlCl3 +3 Na OH = Al (OH)3! +3 Na Cl

2 Al ( OH)3 = Al2 O3+ 3 H2O

Al2O3 + 3 H2  = 2Al +3 H2O

2Al + 2NaOH +6 H2O =2 Na { Al (OH )4} +3 H2

2Na {Al (OH)4 + 4 H2 SO4  = Na 2 SO4 + Al 2 (SO4)3 +8 H2O