Question

Решите уравнение:
10x^2-(2x-3)(5x-1)=31
(x-2)(x-3)-(x+1)(x-4)=0

Answer 1

$10x^2-(2x-3)(5x-1)=31 10x^2 - 10 x^{2} + 2x + 15x = 31 + 3 17x = 34 x = 2$
$(x-2)(x-3)-(x+1)(x-4)=0 x^{2} - 3x - 2x + 6 - x^{2} + 4x - 1x +4 = 0 - 3x - 2x + 4x - 1x = - 4 - 6 - 3 x = -10 x = 10/3$

Answer 2

Спасибо)

Answer 3

не за что)