Question

(6/у^2-9+1/3-у)*у^2+6у+ 9/5

Answer 1

1)6/(y-3)(y+3) -1/(y-3)=(6-y-3)/(y+3)(y-3)=-(y+3)/(y+3)(y-3)=-1/(y-3)
2)-1/(y-3)*(y+3)²/5=-(y+3)²/5(y-3)=(y+5)/5(3-y)