Question

(-- две третьих + 4.32) - (6.82-одна шестая)   прошу помогите!!!

Answer 1

$(-- frac{2}{3}+4.32)-(6.82- frac{1}{6})=( frac{2}{3}+4 frac{32}{100} )-(6frac{82}{100}- frac{1}{6})= \ frac{2}{3}+ frac{432}{100}- frac{682}{100}+ frac{1}{6}= frac{4+1}{6}+ frac{432-682}{100}= frac{5}{6}- frac{250}{100}= frac{5}{6}- frac{5}{2}= frac{5-15}{6}$$=-1 frac{2}{3}$

Answer 2

(-2/3 + 4.32) - (6.82-1/6)=
 
=-2/3+1/6 + 4.32-6.82=
=(-4+1)/6 - 2,5=
=-3/6-2,5=
=-0,5-2,5=
=-3