Question

$18(frac{1}{3}+1frac{1}{2}+2frac{1}{9})$

Answer 1

$18(frac{1}{3}+1frac{1}{2}+2frac{1}{9})=frac{18}{3}+18*frac{3}{2}+18*frac{19}{9}=6+9*3+2*19=\=6+27+38=71.$