Question

Срочно!!!
1cos^2x=2tg^2x

Answer 1

$frac{1}{cos^2(x)} = 2tg^2(x) <=> 1 + tg^2(x) = 2tg^2(x) <=> tg^2(x) = 1 <=>\ <=> tg(x) = 1;\ \ x = left[begin{array}{c} arctg(1) + 2pi k\ pi + arctg(1) + 2pi nend{array}right k,n in mathbb Z\ \ x = left[begin{array}{c} frac{pi}{4} + 2pi k\ frac{5pi}{4} + 2pi nend{array}right k,n in mathbb Z$

Answer 2

Ну... тут обычно решение просят =)