Question

Решите систему уравнений 
(2х+3)^2=5y    
(3x+2)^2=5y

Answer 1

$left { {{(2x+3)^2=5y} atop { (3x+2)^2=5y}} right.$

(2х+3)²=(3x+2)²
4x²+12x+9=9x²+12x+4
4x²-9x²=4-9
-5x²=-5
x²=1
x1=1  x2=-1

Answer 2

(2*x+3)^2 = 5*y
(3*x+2)^2 = 5*y
есть:
y = 1/5
x = -1
и
y = 5
x = 1