Question

сократите дробь
$2-5p-2k+5pk \ 10p ^{2} -9p+2$

Answer 1

2(1-k)-5p(1-k)=(1-k)(2-5p)
10p²-9p+2=10(p-2/5)(p-1/2)=(5p-2)(2p-1)
D=81-80=1
p1=(9-1)/20=2/5
p2=(9+1)/20=1/2

(2-2p-2k+5pk)/(10p²-9p+2)=(1-k)(2-5p)/(5p-2)(2p-1)=-(1-k)/(2p-1)=(k-1)/(2p-1)